Thread: why a[i][j]=2 in this program

In the below program, I wonder what it means by a[i][j]=2 and why they have used this. Does it mean value of a[i][j]=2, then how come that value..i'm confused

Code:

int main (void)
  {
     int a[3][2];
     int i,j;
 
     for (i=0; j<3; i++)
       for (j=0; j<2; j++)
           a[i][j] =2;
  
     for (i=0; i<3; i++)
        for (j=0; j<2; j++)
           printf ("value in array %d\n", a[i][j]);
 
     for (i=0; i<3; i++)
        for (j=0; j<3; j++)
           print ("value in array %d and address is %P\n", a[i][j], (void*) &a[i][j]);
    
    return 0; 
}

The first loop in initializing each element of the array to 2 with the line a[i][j] =2;. This value is just to show how to initialize an array. You could use any valid value in place of the 2.

Jim

the first loop structure initailize the array to 2.

Thanks again. But what does that mean "initialize the array to 2". Does it mean [2][2] array?

See this link on arrays.

Jim

Originally Posted by learning_grc

Thanks again. But what does that mean "initialize the array to 2". Does it mean [2][2] array?

An array is a bunch of boxes. Each box holds something... array[6] = 2 ...means store the number 2 in box #6.

In your case the areay is organized as 3 rows of 2 columns each... array[2][1] = 2... means go down to row 2 then over to clumn 1 and drop a 2 in there.

For the purposes of the example in message #1... it could be any value, the point is to demonstrate how to initialize (preset) an array of boxes to a specific value, which is used in programming all the time.